<span class='text_page_counter'>(1)</span><div class='page_container' data-page=1>
so
clAo puc
vA
Blo
rAo
udNc
ru,$
x?
fiu
CHQN
Eor
r{rYEN HQC SINH
Cr6r DqITHI
QG
NAU
Hec
2oto -
zalt
luc hrcmg tdc gIAa Z ltrOl tr.u.
Dd
chinh
thtfrc
of
rur
$ION
vAT
Lf
Thdi gian tdm bdi: t80 <sub>phrtt &hbng </sub>k€ thdi giarc phdt
di)
Ngly
thi: 31.thang 10 ndm 2CI10
(D0 thi gdm
c6:
02 trang)
C0u 1.: (3 tli6m).
MQt qud c6u nho treo & dAu mQt dfiy nhg clhi i,dAu kia crla d0y c6 dinh tai A.T4i
rti€m O dudi A mQt doqn
{
,n"o phuong thAng dring c6 mQt dinh.K6o quA cAu di5n
vi
2a
tri
diy
<sub>.ye</sub>AB nim ngang
vi
tha nhe ra.
a.Tffi ti
s0 lUc cdng dffy ngay trvffc
vi
sau khi ddy chpm dinh khi
qui
c6u qua
^ ':
v!
til
can Dang.
b. Xdc dinh
vi tri
trOn
qu!
d4o cua qu6 cAu tai d6 lpc cdng d0y treo
bing
O,vfln
t5c cua qud cAu ltic d6 bing bao nhi6u? Siu d6 qu6 cdu chuy6n dQng nhu thi5
nio
vi
lOn d6n d6 cao lcrn nh6t crich di6rn ffeo bao nhi0u?
Cilu 2: (3 rli6m)
Hai hinh t4r dOng
chlt
01, 02cd khOi luqng m1
*
<sub>10kg, </sub><sub>trt2 </sub>
<sub>= </sub>
<sub>30kg d4t </sub><sub>tiOp </sub><sub>xric </sub><sub>nhau </sub><sub>trdn </sub><sub>hai </sub>rn{t
phing nghiCng nhan (Pr), (Pz), vudng g6c, nghiOng
g6c a <sub>= 600 </sub>nhu hinh v€"
fim:
a. G6c tpo boi OrOz
vi
rn{t phing (P1).
b. Ap lgc cria c6c khi5i
ku
16n <sub>-c6c </sub>mfit. phing vd 6p
(b6 qua mgi ma s6t, l6y g <sub>= </sub>10mls2)
Ciu
3: (3 tli6m)
MQt trong nhirng <tQng co diit ffong
l}m
vi$c o hai
k!
dAu ti6n nhu sau:
+
Kh6ng
kfri
vi
nhi0n ligu cho
vio
xylanh,
0
cui5i
pha ngp kh6ng khf 0 tril)g thei A (pr,Vr-,Tr)
;
Nhi0n 1i0u
bi
oot cnay (pha nd)
lirn
6p suAt tang
tlQt ngQt trong th€ tfch kh6ng eOi va t?o ra sg truyAn nhi$t
Q1, cr.l6i pha
nly
k*rf cdn 14i 0 tr4ng thdi B (pz, Vr, Tz)
+ Ti6p theo khi duqc ddn doan nhiQt dOn tr4ng tttdi C
(pr, Vz,
\).
Cdc th6ng sO <sub>U </sub>On dinh, bi6t trudc.
+ CuOi cung.khi trong xylanh dugc thodt ra 0 6p su6t
khOng d6i p1 vh chu trinh moi bat dAu.
86
qua lugng nhiOn liQu long, xem khdng khi
vi
khi chdy nhu
h
khf
ly
tucrlg.
HQ sO Po6tx6ng <sub>T </sub><sub>= </sub>1,4
a.
Tffi
c6ng
A
trao d6i boi m$t mol
lhi
sau mQt chu trinh theo
yv)
c6c nhiet d0
T1, T2, T3.
b. Tinh hiQu su6t dOng co. Cho a <sub>=</sub>
b=4
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{s
Ciu
4: (3fr.0m)
MQt khung d6y
hinh
vu6ng ABCD, cpnh
a
<sub>= </sub>
20
cm,
ctiQn tr& t6ng cQng R <sub>= </sub>0,8f,1, tr6n d6 c6 cicngudn Er=
12V;
11
= 0,1f,); Ez
<sub>= </sub>
8V; rz <sub>= </sub>0,1C)
mic
nhu hinh v6. Mach
dugc
dit
trong
tt
trudmg ddu
E
vudng g6c vdi mat ph&ng ctra khung.
a. Cho
E
tangtheo
thli
gian b6ng quy lu{t B <sub>= </sub>
kt
( k <sub>= 40T/s). </sub>Xdc elinh dbng iliQn
I
qua khung ddy.
b. Ei5 ddng diQn qua khung dey bang 0, t& trudrng phAi thay
d6i thii ndo?
t
Er
Ez r?
C6u5:Gifr6m)
-
Ba
qui
cAu c6 ttr6 ffugt khdng ma s6t tr6n
mQt
3 ; 1
z
thanh cung,
minh
nirn
ngang. Bi6t kh6i tugng
hai
<sub>O 3 </sub>
<sub>bffiE[$oo</sub>
qui
ciu
t
vi
2
ld
m", <sub>= </sub>ffiz <sub>= </sub>
ffi;
}d xo c6 d0 cirng K
vi
c6 lrtr6i tugng kh6ng d6ng ke. <sub>QuA cAu </sub>3 c6 kh6i lugmg
n\=+.
Lric dAu hai qu6 cAu
'2
1,2 dtmg yOn, ld xo c6 dO dei tU nhi6n lg.TruyAn cho m, vfln tdc ilo dtin va ch4m di'n
tr6i
vio
3:xffclpm,
khoi r6m G cu6 hQ chuyen dQng nhu th6 nio? Tim van t6c cu6
tctrOi tam C.
b. Chring minh
ring
hai
qui
cAu 7 vir2 dao dQng diAu
hoi
quanh
vi
ui
c6 Ainn
OOi voi G. Tim chu kj,
vi
bi6n dQ dao d6ng cu6 cdc vQt.
Ciu
6: (3di6m)
MQt di6m s6ng S dat trOn tr.uc chinh cira mQt thAu kinh hQi tp
.g
d0 lon ti6u cU
\2
cm, cho anh tha; S/.
Khi
ddri S
lai
gAn th6u kinh
6
cm
thi
anh S'
dli
di
2cm
vi
kh6ng ttray dfii tinhch6t. X6c tlinh vi
ti
cria vflt, 6nh ffudc
vi
sau khi dich chuy6n
vft.
CiuT:
(2 ili6m)
Voi
dUng cU
li
mQt b6ng dbn <sub>lopi {22AV </sub>
-
60W). Hdy.nQu phuong 6n do cdng
suAt tieu thU
cla
mQt m6y Alen OunS ffong gia dinh khi dA m6t th6ng tin vC c6ng su6t
tiOu thp cta thitit bi
niy.
HET.
</div>
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